Question

Find two irrational number between√2 and√3

Answer 1

Answer:

$\sqrt{6}$

$\sqrt{2 \sqrt{6} }$

Step-by-step explanation:

1st irrational no. is

$\sqrt{2 \times 3}$

which is

$\sqrt[2]{6}$

and 2nd one is

$\sqrt{2 \times \sqrt{6} }$

Or

$\sqrt{3 \times \sqrt{6} }$