Question

find two irrational number between 3 by 7 and 6 by 11

Answer 1

irrational number between a and b is√ab
if ' a ' be 3/7 and ' b ' be 6/11
then irrational number between them=√3/7×6/11
=√9/77=√9/√77 =
3/√77
now let 'a' be 3/7 and 'b' be 3/√77 then,
irrational number between them= √3/7×3/√77=√9/7√77=
√9/7√77=3/7√77

thus the irrational numbers between 3/7 nd 6/11 is "3/√77" nd "3/7√77"
hope this answer helps u......

Answer 2

Hi friend,

Given numbers,
3/7 and 6/11

An irrational number between two given rational numbers,a and b is √ab
Let a=3/7 and=6/11
One irrational number=√3/7×6/11=√18/77

Now,take a=3/7 and b=√18/77
Irrational number=√(3/7×√18/77)
=√(3√18/7√77)
=18√3/77√7

Another method:-
3/7=0.428...
6/11=0.545...
Two irrational numbers between 3/7 and 6/11 are
0.4727392....
0.5378836...
You can insert any non terminating and non repeating numbers

Hope it helps