Find two irrational numbers lying between √2 and √3
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For rational number:
√2= 1.414 (up to 3 places after decimal place)
√3= 1.732 ( “ “ “ “ )
So, there may be so many rational numbers we can get . Consider for first place of decimal place and if we place the numbers in the number line we see 1.5 is one rational number [3/2] lies in between 1.4 and 1.7. As,
√2<1.5<√3
For irrational number.
We know , both √2 & √3 are irrational number.
So √2+√3 ¡s also irrational. Therefore(√2+√3)/2 is also irrational number. As ,
√2<(√2+√3)/2 <√3, (√2+√3)/2 is one irrational number between √2 &√3.
√2= 1.414 (up to 3 places after decimal place)
√3= 1.732 ( “ “ “ “ )
So, there may be so many rational numbers we can get . Consider for first place of decimal place and if we place the numbers in the number line we see 1.5 is one rational number [3/2] lies in between 1.4 and 1.7. As,
√2<1.5<√3
For irrational number.
We know , both √2 & √3 are irrational number.
So √2+√3 ¡s also irrational. Therefore(√2+√3)/2 is also irrational number. As ,
√2<(√2+√3)/2 <√3, (√2+√3)/2 is one irrational number between √2 &√3.
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