Find two members of Pythagorean triplet in the following when :
(1 One member is 6
(2 One member is 14 (3
One member is 16
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Answered by
6
Answer:
1.Let 2m=6
m=3
m^2+1= 9+1= 10
m^2 -1 =9-1=8
3,8 and 10 form a Pythagorean Triplet.
2.Let 2m=14
m=7
m^2+1 = 49+1=50
m^2-1=49-1=48
14,48 and 50 form a Pythagorean Triplet.
3.Let 2m=16
m=8
m^2+1= 64+1=65
m^2-1=64-1=63
8,63 and 65 form a Pythagorean Triplet.
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Answered by
0
Answer:
8,63,65
Phythagores triplet
Hope u understand
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