Find two multiples of 3 whose product is 108
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12 and 9 are the multiple s of 3 and when we multiply them we get 108
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9 and 12
Just divide 108 using the HCF ( highest common factor) until the lowest divisible value by 3 comes which is 12.Mulitiply the 3 by 3 in the factors and multiply that by 12
Just divide 108 using the HCF ( highest common factor) until the lowest divisible value by 3 comes which is 12.Mulitiply the 3 by 3 in the factors and multiply that by 12
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