find two natural number the sum of whose square's 25 times there sum and also equal to 50 times the difference
Answers
Answered by
0
Answer:
putting x in (1)
x² + y² = 25(x+y)
⇒ (3y)² + y² = 25(3y+y)
⇒9y²+y²=25×4y
⇒10y²=100y
⇒y² = 10y
⇒ y = 0 or 10
but y≠0 as y is a natural number
So y = 10
x = 3y = 30
two numbers are 10 and 30
Similar questions