find two natural number whose sum square is 25 times theirs the sum and also equal to 50 times their the difference
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the sum of whose squares is 25 times their sum and also equal to 50 times their difference. ... Let the required natural numbers be a and b. Then, a2+b2=25(a+b) and (a2+b2)=50(a-b).23-Jul-2020
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