Question

Find two natural numbers differ by 3 and sum of their squares is 29 ​

Answer 1

Answer:

The two natural numbers are 5 and 2 which differ by 3 and their squares is 29.

Hope it helps you!

Answer 2

Answer:

Let one of the natural numbers be ‘a’

Given, the numbers differ by 3.

⇒ 2nd number = a + 3

⇒ a2 + (a + 3)2 = 117

⇒ a2 + a2 + 6a + 9 = 117

⇒ a2 + 3a – 54 = 0

⇒ a2 + 9a – 6a – 54 = 0

⇒ a(a + 9) – 6(a + 9) = 0

⇒ (a – 6)(a + 9) = 0

⇒ a = 6, - 9

Thus, the numbers are 6, 9