Find two natural numbers in 5:7 such that their l. c. m. is 210
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let's first number =5x
second number=7x
HCF=x
5x×7x=210×x
35x^2=210×x
x^2/x=210/35
x=6
so first no. is 5×6=30
second no.7×6= 42
second number=7x
HCF=x
5x×7x=210×x
35x^2=210×x
x^2/x=210/35
x=6
so first no. is 5×6=30
second no.7×6= 42
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