Find two natural numbers nearest to 10000 which are exactly divisible by each of 2, 3, 4, 5, 6 and 7(with steps please)
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9660 & 10080 are the 2 nearest number of 10,000, which are divisible by 7,6,5,4,3,2. Just take only 23 and before number that is 22 then multiply to get nearest to 10000 which is exactly divisible by 7,6,5,4,3,2. Therefore the numbers are 420×23,420×22=9660;9240.
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