Math, asked by chakms, 11 months ago


Find two natural numbers which differ by 5
and whose squares have the sum 125.​

Answers

Answered by manishapandey1090
0

Answer:

let no be x and y

and is 10 and 15

Attachments:
Answered by gauravkumaya
0

Answer:

The two natural numbers are 5 & 10

Step-by-step explanation:

Difference = 10 - 5

= 5

square of 5 = 5*5

= 25

square of 10 = 10*10

= 100

Sum of the squres of 5 & 10 = 25 + 100

= 125

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