Question

find two no.s each of 3 digits , soch that their HCF is 7 and LCM is 3059

Answer 1

Answer:

Hey friend...

Your answer is given below...

Solution :

Let the required number be 80a & 80b,

Where, a and b are divisible by each other

Then, 80a × 80b = 80 × 5760

a × b = 80 × 5760 / 80 × 80

ab = 72

(a = 1, b = 72) or (a = 8, b = 9)

• Possible combinations of numbers

= (80 × 1, 80 × 72) or (80 × 8, 80 × 9)

The three digits numbers out of these would be :

= 640 & 720 (Answer)

# I hope it will help you.

Answer 2

Answer:

133 and 161

Step-by-step explanation:

Let the two numbers be 7x and 7y.

LCM of two numbers is 3059.

7xy = 3059

xy = 437

So the prime factors are 19 and 23.

x = 19 and y = 23 or x = 23 and y = 19.

Therefore, the numbers are 133 and 161.

#Hope my answer helped you.