Question

find two no.s such that one of them exceeds the other the by 9 and their sum is 81

Answer 1

Let the nos. be "x"-
A/Q-
(x+9)+x=81
x+9+x=81
2x+9=81
2x=81-9
2x=72
x=72/2
x=36
therefore the nos. are-
{(36)+9} +(36)
=45 + 36
so,the nos. are - 45,36
Hope I helped you!!!

Answer 2

Let the required numbers be x and x+9

Now,x+x+9=81
2x+9=81
2x=81-9
2x=72
x=36

Now we got one of the numbers i.e x =36
so x+9 would be:-
36+9=45

So the required two numbers are 36 and 45...

Hope this helps u..................^_^