Question

Find two no. Whose sum is 28and product is 128

Answer 1

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Answer 2

Step-by-step explanation:

Let the two numbers be x and y

according to problem,

x + y = 28

y = 28 - x ----------------------eqn(1)

according to problem,

xy = 128 --------------–-------eqn(2)

substitute y = 28-x in eqn(2)

$x(28 - x) = 128$

$28x - {x}^{2} = 128$

${x}^{2} - 28x + 128 = 0$

${ x }^{2} -16x - 8x + 128 = 0$

$x(x - 16) - 8(x - 16) = 0$

$(x - 16)(x - 8) = 0$

$x - 8 = 0$

$x = 8$

Put x = 8 in eqn(2)

8y = 128

y = 128/16

y = 8

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