Math, asked by Anonymous, 1 year ago

Find two number of three digits each which have HCF 80 and LCM 5760.

Answers

Answered by Niruru
18
Hey friend...

Your answer is given below...

Solution :

Let the required number be 80a & 80b,

Where, a and b are divisible by each other

Then, 80a × 80b = 80 × 5760

a × b = 80 × 5760 / 80 × 80

ab = 72

(a = 1, b = 72) or (a = 8, b = 9)

• Possible combinations of numbers
= (80 × 1, 80 × 72) or (80 × 8, 80 × 9)

The three digits numbers out of these would be :
= 640 & 720 (Answer)

# I hope it will help you.

Answered by Anonymous
2

I hope u like my answer

Thanks for asking question

Thank you

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