Find two number of three digits each which have HCF 80 and LCM 5760.
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Answered by
18
Hey friend...
Your answer is given below...
Solution :
Let the required number be 80a & 80b,
Where, a and b are divisible by each other
Then, 80a × 80b = 80 × 5760
a × b = 80 × 5760 / 80 × 80
ab = 72
(a = 1, b = 72) or (a = 8, b = 9)
• Possible combinations of numbers
= (80 × 1, 80 × 72) or (80 × 8, 80 × 9)
The three digits numbers out of these would be :
= 640 & 720 (Answer)
# I hope it will help you.
Your answer is given below...
Solution :
Let the required number be 80a & 80b,
Where, a and b are divisible by each other
Then, 80a × 80b = 80 × 5760
a × b = 80 × 5760 / 80 × 80
ab = 72
(a = 1, b = 72) or (a = 8, b = 9)
• Possible combinations of numbers
= (80 × 1, 80 × 72) or (80 × 8, 80 × 9)
The three digits numbers out of these would be :
= 640 & 720 (Answer)
# I hope it will help you.
Answered by
2
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