Question

find two number such that one is 5 times the other and their differences is 20​

Answer 1

Answer:

let the numbers be x and y.

AQ,

$x = 5y$

and

$x - y = 20$

from these equation we got

x-y=20

5y-y=20

4y=20

y=5

so that

x=5×5=25

the required numbers are 5 and 25

Answer 2

Answer:

let one number is X

so, second number=5X

A/Q

5X-X=20

4X=20

X=5ans

therefore,

5X=5×5

=25ans

therefore, number=5;25 ANS.......

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