Question

find two number such that one of the number exceeds the otjer by 7 and their sum is 69

Answer 1

let the first number be x and second number be x+7.

therefore x+x+7=69

2x+7=69

2x=69-7

2x=62

x=62/2

x=31

hence, first no.=x=31

second no.=x+7=31+7=38

hope this helps u....

Answer 2

Let one number be x,other number be x+7
Their sum = 69
x+x+7 =69
2x+7 =69
2x=69-7
2x = 62
X = 62/2 = 31

Therefore the one number is 31
Other number = x+7 =31+7 =38