find two number such that one of them exceed the other by 18 and their sum is 92
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Answered by
1
Answer:
37,55
Step-by-step explanation:
let the two numbers be x and y
now
x=y+18 ......(i)
x+y=92
putting the value of x we get
y+18+y=92
⇒2y=92-18
⇒2y=74
⇒y=74/2=37
y=37
x=y+18=37+18=55
Answered by
0
answer 37 and 55...
thank me
thank me
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