Find two number such that one of them exceed the other by 8 and their sum is 80
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Let one number be 'x'
Other number is x + 8
From question we get that ,
x + x + 8 = 80
2x = 72
x = 72/2
x = 36
x + 8 = 36 + 8 = 44
Two Number are 36 & 44 ✔
Other number is x + 8
From question we get that ,
x + x + 8 = 80
2x = 72
x = 72/2
x = 36
x + 8 = 36 + 8 = 44
Two Number are 36 & 44 ✔
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0
Answer:
divide 84 into two part such that 1/4 of one part is equal to 1/3 of the other part.
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