Question

find two number such that one of them exceeds the other by 18 and their sum is 92.

Answer 1

Hey


Let one number be x .


Now ,

other number exceeds first by 18 .


So ,


other number = ( x + 18 )


Now ,


Sum of these numbers = 92


=> x + x + 18 = 92


=> 2x = 74


=> x = 37

first number = 37


Second number = 37 + 18


= 55


thanks :)

Answer 2

let the no be x then
ATQ
x+x+18=92
2x=92-18
2x=74
x=74÷2
×=37
so 1st no =37
2nd no = 37+18=55