find two number such that one of them exceeds the other by 18 and their sum is 93
neha2310:
sorry yha pr 92 hoga
Answers
Answered by
1
let one number be x say
second number=x+18
sum=93
x+x+18=93
2x=93-18
2x=75
x=75/2
x=37.5
x+18=37.5+18=55.5
second number=x+18
sum=93
x+x+18=93
2x=93-18
2x=75
x=75/2
x=37.5
x+18=37.5+18=55.5
Similar questions