Question

find two number such that one of them is five times the other and their diffrence is 132 explain by process
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Answer 1

$\huge{\star}{\underline{\boxed{\red{\sf{Answer :-}}}}}{\star}$

Let the first number be x and second number be y.

So,

A.T.Q

x = 5y ..........(1)

x - y = 132 ........(2)

From equation 1.

Put value of x in equation 2.

5y - y = 132

4y = 132

y = 132/4

y = 33

$\huge{\underline{\boxed{\blue{\sf{y = 33}}}}}$

Put Value of y in equation 1.

x = 5(33)

x = 165

$\huge{\underline{\boxed{\blue{\sf{x = 165}}}}}$

Verification :-

For verification put value of x and y in equation 1 and 2.

When value of x and y is putted in equation 1.

165 = 5(33)

165 = 165

Noe, in equation 2.

165 - 33 = 132

132 = 132

Hence Proved