Math, asked by kumarshawvijay200, 1 day ago

find two number such that one of them is five times the other and their differences is 132​

Answers

Answered by tennetiraj86
3

Answer:

165 and 33

Step-by-step explanation:

Solution :-

Let the other number be X

Then, one of the numbers = Five times the other

=> 5X

Their difference = 5X - X = 4X

According to the given problem

Their difference = 132

=> 4X = 132

=> X = 132/4

=> X = 33

The other number = 33

One of the numbers = 5X = 5(33) = 165

Therefore, The two numbers = 165 and 33

Answer:-

The required two numbers are 165 and 33

Check :-

The two numbers = 165 and 33

Their difference = 165-33 = 132

165 can be written as

=> 165 = 5×33

=> 165 = 5 times 33

Verified the given relations in the given problem.

Answered by ItzNobita50
56

Given:-

  •  \tt \: One  \: number \:  is \:  5 \:  times   \\  \tt\:  \: the \: other \: number.
  •  \tt \: Their \:  Sum \:  is  \: 132.

To Find:-

  •  \tt \: Number s

Let us assume:-

 \sf \: Let  \: the  \: first  \: number \:  be  \: 5x

 \tt \: Then \:  other \:  number  \: is  \: x

Solution:-

According to the question:-

  \boxed{\bf5x - x = 132} \\  \boxed { \bf \: 4x = 132 \:  \:  \:  \:  \:  \:  \: } \\  \boxed{ \bf \: x =  \frac{132}{4} \:  \:  \:  \:  \:  \:  \:  \:  } \\  \boxed{ \red { \bf \: x = 33 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: }}

Henceforth,

  •  \boxed { \bf \: First \:  number \: = \:  5x=165}
  •  \boxed { \bf  \: Second  \: number= x=33}

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