Question

Find two number whose sum is 16 and one of them exceeds the other by 4​

Answer 1

Answer:

One number=6

Another number= (6+4)= 10

Step-by-step explanation:

$Let\ one\ of\ the\ numbers\ be\ x.\\Therefore,\ another\ number\ =\ (x+4)\\According\ to\ the\ question,$

$(x) + (x+4) = 16 \\x+x+4=16 \\2x+4=16 \\2x=16-4 \\ 2x=12 \\ x=12/2 \\x=6$

$One\ number\ =\ 6 \\Another\ number\ =\ (6+4)= 10$