Question

find two number whose sym is 27 and product is 182​

Answer 1

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Let the first number be x and the second number is 27 - x. It is given that the product of these numbers is 182.

Let the first number be x and the second number is 27 - x.

Therefore, their product = x (27 - x)

It is given that the product of these numbers is 182.

Therefore, x(27 - x) = 182

⇒ x2 – 27x + 182 = 0

⇒ x2 – 13x - 14x + 182 = 0

⇒ x(x - 13) -14(x - 13) = 0

⇒ (x - 13)(x -14) = 0

Either x = -13 = 0 or x - 14 = 0

⇒ x = 13 or x = 14

If first number = 13, then

Other number = 27 - 13 = 14

If first number = 14, then

Other number = 27 - 14 = 13

Therefore, the numbers are 13 and 14.

Answer 2

Step-by-step explanation:

Let the 2 no.s be x and y.

Given that x+y = 27...(1)

Product = xy = 182...(2)

Substituting the value of x in (2) and putting in (1)

xy = 182

x = 182/y

x+y = 27

182/y+y = 27

182+y² = 27y

182-27y+y² = 0

By putting the formula of Quadratic Equation ,

y = 13

x+y = 27

x = 27-13 = 14

The no.s are 13 and 14..

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