Find two numbers, if Their sum is 3 and their difference is 21
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Answer: The numbers are -9 and 12.
Let the no.s be a and b,
ATQ,
a + b = 3 --------------------> i
a - b = 21 -------------------> ii
(ii) - (i), we get,
a - b = 21
a + b = 3
- - -
-2b = 18
therefore, b= 18÷-2
= -9
Putting b = -9 in (i), we get,
a + b = 3
a +(-9) = 3
a = 3 + 9
Therefore, a= 12
Therefore, the two numbers are 12 (a) and -9 (b).
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