Find two numbers in the ratio of 8 : 7 such that when each is decreased by 12 they are in ratio 11:9.
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Answer:
Ratio = 8:7
Consider the numbers as 8x and 7x
They are decreased by 12
2
1
=
2
25
Sp, using the condition
[7x–
2
25
]
[8x–
2
25
]
=
9
11
Taking LCM
[
2
(14x–25)
]
[
2
(16x–25)
]
=
9
11
By further calculation
(14x–25)
(16x–25)
=
9
11
By cross multiplication
154x–275=144x–225
154x–144x=275–225
10x=50
x=
10
50
=5
So the numbers are
8x=8×5=40
7x=7×5=35
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