find two numbers nearest 1000 which are exactly divisible by 6.,15,28,42 and 48
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Answer:
1680 & 3360
Step-by-step explanation:
find two numbers nearest 1000 which are exactly divisible by 6.,15,28,42 and 48
First we will find the number exactly divisible by 6,15,28,42 and 48
For that we will find LCM (lowest common multiplier of these)
6 = 2 * 2
15 = 3 * 5
28 = 2 * 2 * 7
42 = 2 * 3 * 7
48 = 2 * 2 * 2 * 2 * 3
LCM = 2 * 2 * 2 * 2 * 3 * 5 * 7 = 1680
Next number would be 1680 * 2= 3360
Two numbers are 1680 & 3360
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