Math, asked by tabrejahmad7034, 1 year ago

Find two numbers nearest to 100000 which are divisible by each 1, 2, 3, 4, 5,6 ,7 ,8 ,9 and 10

Answers

Answered by nidhikaarora
3

Answer:

10080

Step-by-step explanation:

LCM of (3, 4, 5, 6, 7, 8) = 3 × 4 × 5 × 7 × 2 = 840

⇒ divided 10000 by LCM

⇒ $$\frac{{10000}}{{840}},$$   we get remainder = 760

Now two possibilities are

= 10000 - 760 = 9240

or 10000 + (840 - 760) = 10080

So, nearest number is = 10080

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