Math, asked by tabrejahmad7034, 10 months ago

Find two numbers nearest to 100000 which are divisible by each 1, 2, 3, 4, 5,6 ,7 ,8 ,9 and 10

Answers

Answered by nidhikaarora
3

Answer:

10080

Step-by-step explanation:

LCM of (3, 4, 5, 6, 7, 8) = 3 × 4 × 5 × 7 × 2 = 840

⇒ divided 10000 by LCM

⇒ $$\frac{{10000}}{{840}},$$   we get remainder = 760

Now two possibilities are

= 10000 - 760 = 9240

or 10000 + (840 - 760) = 10080

So, nearest number is = 10080

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