Question

Find two numbers nearest to 8888888 which are exactly divisible by 2915

Answer 1

Answer:

88,87,835 and 88,90,750

Step-by-step explanation:

88,87,835 =2915*3049 , 8890750 = 2915*3050

Answer 2

$To \: find \: two \: numbers \: nearest \:to \\8888888 \:which \:are \: exactly \: divisible \\by \:2915 , we \: have \: do\:the\:division .$

2915 ) 8888888 ( 3049

******** 8745

______________

*********** 1438

*********** 0000

______________

*********** 14388

*********** 11660

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************* 27288

************* 26235

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Remainder (1053 )

________________

$Nearest \: \:to \:8888888 \:which \:is \: exactly\\ \: divisible \:by \:2915 = 8888888 - Remainder \\= 8888888 - 1053 \\= 8887835$

$Another \: number = 8887835 - divisor \\= 8887835 - 2915 \\= 8884920$

Therefore.,

$\red{ Two \: numbers \: nearest \:to }\\\red{8888888 \:which \:are \: exactly \: divisible} \\\red{by \:2915 \: are }\\\green {\: 8887835\: and \: 8884920}$

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