find two numbers such as one of them is five times the other and their difference is 132.
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according to question.
let first number =x
second number =y
so,
x=5y.
now, from qustion.
y–x=132.
y= 132+x
y=132 + 5y. (^x=5y).
now .
–4y=132 .
y= –33.
and first number is
x= –165.
.
varification.
y–x=132
–33–(–165)=132
–33+165=132
132=132.
hence the numbers are –33 and –165.
there is possible for another answer because this question contains many solutions...
(may be the answer is 33&165 if you use different between them oppositly)
let first number =x
second number =y
so,
x=5y.
now, from qustion.
y–x=132.
y= 132+x
y=132 + 5y. (^x=5y).
now .
–4y=132 .
y= –33.
and first number is
x= –165.
.
varification.
y–x=132
–33–(–165)=132
–33+165=132
132=132.
hence the numbers are –33 and –165.
there is possible for another answer because this question contains many solutions...
(may be the answer is 33&165 if you use different between them oppositly)
rishav591:
answer is 33 and 165
i already told . if you use difference between them oppositly then answer will be 33 & 165. otherwise –33&–165. see carefully
you have written 33 and 65 see
yes, i corrected now....
thanks
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