Question

Find two numbers such that exceeds the other by 11 and their sum is 73

Answer 1

Answer:

Let one number be x,

Then other number is x+11

Now According to the question,

$= > (x) + (x+11) = 73 \\ = > 2x = 73 - 11 \\ = > x = \frac{62}{2} = 31$

So first number is 31 (x) and other number is 42 (x+11)

Please mark my answer as the BrAiNlIeSt Answer.....

Answer 2

Answer:

Let the number be x.

First number = x

Second number = x + 11

Their sum = 73

=> x + x + 11 = 73

2x + 11 = 73

2x = 73 - 11

2x = 62

x = 62/2

x = 31

So,

First number = x = 31

Second number = x + 11 = 31 + 11 = 42

Check :

31 + 42 = 73 ✔️

HOPE IT HELPS ❤️

THNKX MY ANSWERS ❤️