Question

Find two numbers such that half the first equals one third of the second and twice their sum exceeds three times the second by 4.
Please answer it fast.....
​

Answer 1

open the full photo to get the answer, hope it helps

Answer 2

Answer:

The two numbers is $8,12$

Step-by-step explanation:

Given: Number

To find: Two numbers

let x and y be the 1st and the 2nd number.

the 2 equations are: $\frac{x}{2} =\frac{y}{3}$

Therefore, $x=\frac{2y}{3} ----- 1$

$2 (x+y)=3y+4 -------- (2)$

Substitute $(1) in (2)$

$2 (\frac{2y}{3} +y)=3y+4 \\\frac{4y}{3} +2y=3y+4 \\4y+6y=9y+12 \\y=12$

Put y=12 in the equation in (1)

$x=\frac{2y}{3}\\x=\frac{24}{3}\\\\x=8$

The two number is $8,12$