find two numbers such that one exceeds the other by 11 and their sum is 73
Answers
Answered by
26
Question :
Find two numbers such that one exceeds the other by 11 and their sum is 73 .
Answer : 42,31 .
Solution:
Let the smaller number be x .
Then, the greater number be x+11.
Sum of both numbers is 73
So, (x + 11) + x = 73
2x + 11 = 73
2x = 73 - 11
2x = 62
x = 62 /2
x = 31 .
Hence, the smaller number = x = 31.
And the greater number is = 11 +x = 11 + 31 = 42.
Verification of the required answer :
One exceeds the other by 11 so their difference must be 11 .
42 - 31 = 11
Sum of both numbers must be 73.
42 +31 = 73.
Hence,the answer is verified.
Answered by
5
Answer:
31,42
Step-by-step explanation:
Let the first number be X
then the second number be X + 11
ATQ
x+(x+11)=73
=x+x=73-11
=2x=62
=x=31
1st no. =31 Ans.
2nd no=x+11
=31+11
=42 Ans.
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