Question

find two numbers such that one exceeds the other by 11 and their sum is 73

Answer 1

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Question :

Find two numbers such that one exceeds the other by 11 and their sum is 73 .

Answer : 42,31 .

Solution:

Let the smaller number be x .

Then, the greater number be x+11.

Sum of both numbers is 73

So, (x + 11) + x = 73

$\longrightarrow$ 2x + 11 = 73

$\longrightarrow$ 2x = 73 - 11

$\longrightarrow$ 2x = 62

$\longrightarrow$ x = 62 /2

$\longrightarrow$ x = 31 .

$\longrightarrow$ Hence, the smaller number = x = 31.

And the greater number is = 11 +x = 11 + 31 = 42.

Verification of the required answer :

One exceeds the other by 11 so their difference must be 11 .

$\longrightarrow$ 42 - 31 = 11

Sum of both numbers must be 73.

$\longrightarrow$ 42 +31 = 73.

Hence,the answer is verified.

Answer 2

Answer:

31,42

Step-by-step explanation:

Let the first number be X

then the second number be X + 11

ATQ

x+(x+11)=73

=x+x=73-11

=2x=62

=x=31

1st no. =31 Ans.

2nd no=x+11

=31+11

=42 Ans.

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