Question

find two numbers such that one is four times the other and their difference is93

Answer 1

HEYA
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Let one number be X

The other number = 4X

According to the given question

4X - X = 93

3X = 93

X = 31

The numbers are 31 and 124

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Answer 2

Let's gather the information given:

1.There are 2 numbers whose difference is 93.

2.One of the number is 4 times the other number.

So,if we take the smaller number's value as x,then the value of the larger number will be 4*x=4x.

It is also given that their difference is 93.

So,

4x-x=93.

Subtracting 4x-x:

3x=93.

Sending(transposing) 3 to RHS to divide 93 by 3:

x=93/3.

x=31.
4x=4(31)=124.

Therefore, the 2 numbers are 124 and 31.
Here 124 is 4 times 31(as required) and 124-31=93(as required).