Question

find two numbers such that one is four times the other and their difference is 93

Answer 1

let one no. be x
then second no is 4x
A/Q
4x-x=93
3x=93
x=31

first no =31
second no =31×4=124

Answer 2

let the number - x
according to question one no. is 4 times other so another no. is - 4×x - 4x
now as it is written in question that there difference is 93 so
4x-x=93
3x=93
x=93/3
x=31
The first no. is x =31.
Another no. is 4x=4×31=124.