Question

Find two numbers such that one of exceeds the other by 13 and their sum is 77​

Answer 1

First no. is 32 and the other no. is 45

Let the nos. be x and y,

x=y+13

Atoq,

x+y=77

y+y+13=77

2y=64

y=32

x=45

Answer 2

Answer:

Step-by-step explanation:

Convert given word problem into algebraic

equation.

Let first number = x

Second number = 9 exceeds the first number

Sum of the two numbers = 81

x + ( x + 9 ) = 81

x + x + 9 = 81

2x = 81 - 9

2x = 72

x = 72 / 2

x = 36

Therefore ,

First number = x = 36,

Second number = x + 9 = 36 + 9 = 45

I hope this helps you.