Find two numbers such that one of the exceeds 13 by the other and the sum is 77
Answers
Answered by
2
Answer:
LET THE TWO NO.'S BE X AND X-13.
THEN ,
X+X-13=77
2X+13=77
2X=65
X=65/2 or 32.5
Answered by
4
Answer:
32 and 45 are two numbers
Step-by-step explanation:
Let the first number be x
Second number =13 +x
As per question
13+x+x=77
13+2x=77
2x=77-13
2x=64
x=64/2
x=32
First number =x=32
second number =13+x=13+32=45
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