Question

Find two numbers such that one of the numbers exceeds the other number by 18
and their sum is 78.

Answer 1

☯GIVEN :

• Sum of two numbers = 78

• One number is 18 more than the other.

☯ TO FIND :

• The required numbers.

➲ SOLUTION :

Let the one number be x.

Then, the other number = x+18

• One number is 18 more than the other.

$: \implies {\tt{Sum= 78}}$

$: \implies {\tt{One\:Number+Other\:Number= 78}}$

$:\implies {\tt{x +(x + 18) = 78}}$

$:\implies {\tt{x +x + 18 = 78}}$

$: \implies {\tt{2x+ 18 = 78}}$

$: \implies {\tt{2x = 78-18}}$

$: \implies {\tt{2x = 60}}$

$: \implies {\tt{x = \cancel{\dfrac{60}{2} }}}$

$: \implies{\huge{ \underline{\boxed{ \purple{\bf{x =30}}}}}}$

$\huge{\pink{\therefore}}$ One number is 30.

$\huge{\pink{\therefore}}$ Other number is (30+18)=48.