find two numbers such that one of them exceeds the other by 12 and their sum is 56
Answers
Answered by
2
Answer:
let the two no.s be x,y
ATQ
y=x+12
therefore,
x+y=56
x+x+12=56
2x=44
x=22
thus , y=34
Answered by
1
Answer:
Step-by-step explanation:
Let the smaller no be x
And bigger no be y
From first condition
y=x+12.....1
From second condition
x+y=56........2
From equation 1 and 2
2x=44
x=22
Hence y=34
Two no’s are 22 and 34
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