Question

Find two numbers such that one of them exceeds the other by 18 and their sum is 92

Answer 1

let the number be x
other number = x+18
=> according to question ,

=> x+x+18 = 92
=> 2x = 92-18 => 74

=> x = 74/2 => 37


number = x = 37
other number = x+18 = 37+18 => 55



hope this helps

Answer 2

Let the number is x

The other number is x + 18

According to the given question -


x + x + 18 = 92

2x + 18 = 92

2x = 92 - 18

2x = 74

x = 74/2

x = 37 .

Hence :

The First Number = 37.

The Other Number = x + 18 = 37 + 18 = 55 .


Check :

37 + 55 = 92 .


Hence :

$\bold{First \: Number \: = \: 37}$


$\bold{Second \: Number \: = \: 55}$