Question

Find two numbers such that one of them exceeds The Other by 18 and their sum is 92​

Answer 1

Step-by-step explanation:

x-y=18---(1)

x+y=92----(2)

add1+2

2x=110

x=55

y=92-55

=37

Answer 2

AnswEr :

$\bf{\red{\underline{\underline{\bf{Given\::}}}}}$

One number of them exceeds the other number by 18 and their sum is 92.

$\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$

The two numbers.

$\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$

Let the one number be r

Let the other number be (r+18)

$\bf{\green{\underline{\underline{\tt{A.T.Q\::}}}}}$

$\dashrightarrow\tt{r+(r+18)=92}\\\\\\\dashrightarrow\tt{r+r+18=92}\\\\\\\dashrightarrow\tt{2r+18=92}\\\\\\\dashrightarrow\tt{2r=92-18}\\\\\\\dashrightarrow\tt{2r=74}\\\\\\\dashrightarrow\tt{r=\cancel{\dfrac{74}{2} }}\\\\\\\dashrightarrow\tt{\red{r=37}}$

Thus,

$\underbrace{\sf{The\:1st\:number\:(r)=37.}}}}\\\underbrace{\sf{The\:2nd\:number\:(r+18)=(37+18)=55.}}}}$