Question

Find two numbers such that one of them exceeds the other by 9 and their sum is 81.​

Answer 1

Answer:

Find two numbers such that one of them exceeds the other by 9 and their sum is 81.​

Let two numbers are x, x+9

and their sum =81

x+(x+9)=81

2x+9=81

2x=81-9=72

2x=72

x=36

hence numbers are 36, 45.

Step-by-step explanation:

Answer 2

Answer:

☆ First number =36

☆ Second number = 45

Step-by-step explanation-

Let the small number be $x$

Then,the other number = $(x + 9)$

$∴ x + ( x + 9 ) = 81$

$⟶2x = 81 - 9$

[ on transposing 9 to RHS, it's positive sign changed into negative ]

$⟶2x = 72$

$⟶x = \frac{72}{2}$

[on transposing 2 to RHS ]

$⟶x = 36$

Hence, one number = 36 ,

and the other number = ( 36 + 9 )= 45.