Question

Find two numbers such that one of them exceeds the other by 13
and their sum is 77.

Answer 1

Answer:

First no. is 32 and the other no. is 45

Step-by-step explanation:

Let the nos. be x and y,

x=y+13

Atoq,

x+y=77

y+y+13=77

2y=64

y=32

x=45

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Answer 2

Answer:

32 and 45 are the two numbers

Step-by-step explanation:

Let the first number be xSecond number =13 +xAs per question 13+x+x=7713+2x=772x=77-132x=64x=64/2x=32First number =x=32second number =13+x=13+32=45Hope it helps you