Question

find two numbers such that one of them exceeds the other by 18 and their sum is 92.

Answer 1

Let the first number be a

Second number = a + 18

According to question

a + a +18 = 92

=> 2a = 92 - 18

=> 2a = 74

=> a = 37


First number = 37

Second number = 55

Answer 2

Let one number be x.
Other number= x+18
Now, sum of the numbers is 92.
So,
x+(x+18)= 92
2x+18= 92
2x= 74
x=74/2=37
So, one number is 37 and other number is 37+18=55