find two numbers such that one of them exceeds the other by 9 and their sum is 21
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let one number = x
other number exceeds the other by 9 = x+9
their sum = 21
according to the sum,
x+x+9= 21
2x = 21-9
2x = 12
x = 12/2 = 6
one number = x = 6
second number = x+9 = 6+9 = 15
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p.priyamvatha
other number exceeds the other by 9 = x+9
their sum = 21
according to the sum,
x+x+9= 21
2x = 21-9
2x = 12
x = 12/2 = 6
one number = x = 6
second number = x+9 = 6+9 = 15
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p.priyamvatha
shakti28:
Nice
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