Find two numbers such that one of them exceeds the other by 8 and their sum is 80
Answers
Answered by
0
Answer:
678............................099
Answered by
4
Answer:
36 and 44
Step-by-step explanation:
let one number =x
nd other exceeds by 8 = x+8
thier sum is 80
x+x+8= 80
2x=80-8
2x= 72
x= 72/2
x= 36-------- is one number
nd other is x+8→ 36+8=44-------- is second number
two numbers are 36 and 44
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