Question

Find two numbers such that one of them exceeds the other by 13 and their sum is 77...
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Answer 1

Answer:

The required numbers are 32 and 45..

Step-by-step explanation:

Let the smaller number be x

Then, the largest number = (x+13)

Sum of the two numbers = 77

x+(x+13) = 77

2x+13 = 77

2x = 77 - 13 = 64

x =

$\frac{64}{2}$

= 32

Since x = 32,°..x+13 = 32+13 = 45

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Answer 2

Answer:

two numbers are 32 and 45