Find two numbers such that one of them exceeds the other by 9 and their sum is 81
Answers
Answered by
1
Answer:
Convert given word problem into algebraic
equation.
Let first number = x
Second number = 9 exceeds the first number
Sum of the two numbers = 81
x + ( x + 9 ) = 81
x + x + 9 = 81
2x = 81 - 9
2x = 72
x = 72 / 2
x = 36
Therefore ,
First number = x = 36,
Second number = x + 9 = 36 + 9 = 45
Answered by
1
Answer:
hi army
Step-by-step explanation:
I also purple u but don't give irrelevant answer
Attachments:
Similar questions