Question

Find two numbers such that one of them
exceeds the other by 9 and their sum is
75

Answer 1

Answer:

33, 42

Step-by-step explanation:

Given, one number exceeds the other by 9.

Let one number be x.

Hence, the other number will be x+9.

And, it is stated that their sum is 75.

Therefore, x+(x+9) = 75

2x+9=75

2x=75-9

2x=66

x=66/2

x=33

Since one number is 33, the other number exceeds it by 9, which means it is 33+9 = 42

Answer 2

Answer :

• Smaller number is 33
• Larger number = x + 9 = 33 + 9 = 42

Given :

• Sum is 75

To find :

• Two numbers

Solution :

• Let the smaller number be x
• Larger number be x + 9

Given that,

• Sum is 75

Then,

• x + x + 9 = 75

》x + x + 9 = 75

》2x + 9 = 75

》2x = 75 - 9

》2x = 66

》x = 66/2

》x = 33

• Smaller number is 33
• Larger number = x + 9 = 33 + 9 = 42